The derivative

Find derivatives of monomials and polynomials using the power rule and sum rule, and derive functions from first principles using the limit definition.

Worked examples

Using the power rule to find the gradient at a point

Straightforward

Problem

Let f(x)=5x3f(x) = 5x^3. Find f(x)f'(x) and state the gradient of the curve at x=2x = 2.

Differentiating a polynomial and evaluating the gradient of the tangent

Moderate

Problem

Let f(x)=2x35x2+4x1f(x) = 2x^3 - 5x^2 + 4x - 1. Find f(x)f'(x) and the gradient of the tangent at x=3x = 3.

Finding the derivative from first principles

Challenging

Problem

Use the definition f(x)=limh0f(x+h)f(x)hf'(x) = \lim_{h \to 0} \dfrac{f(x+h) - f(x)}{h} to find the derivative of f(x)=x2+3xf(x) = x^2 + 3x.

Practise

Q1·Straightforward
Let f(x)=x4f(x) = x^4. Use the power rule ddx(xn)=nxn1\dfrac{d}{dx}(x^n) = nx^{n-1} to find f(x)f'(x), then state the gradient of the curve at x=2x = 2.
Q2·Straightforward
Let f(x)=3x2f(x) = 3x^2. Find the gradient of the curve at x=1x = -1.
Q3·Straightforward
Let f(x)=x5f(x) = x^5. Find the gradient of the curve at x=1x = 1.
Q4·Straightforward
Let f(x)=2x3f(x) = 2x^3. Find the gradient of the curve at x=3x = 3.
Q5·Moderate
Let f(x)=x34x2+2f(x) = x^3 - 4x^2 + 2. Differentiate using the sum and scalar multiple rules, then find the gradient of the tangent at x=3x = 3.
Q6·Moderate
Let f(x)=2x43x2+5xf(x) = 2x^4 - 3x^2 + 5x. Find f(1)f'(1).
Q7·Moderate
Let f(x)=4x2x3+1f(x) = 4x^2 - x^3 + 1. Find f(1)f'(-1).
Q8·Moderate
Let f(x)=x3+2x25x+1f(x) = x^3 + 2x^2 - 5x + 1. Find f(0)f'(0).
Q9·Challenging
Use first principles — f(x)=limh0f(x+h)f(x)hf'(x) = \lim_{h \to 0} \dfrac{f(x+h) - f(x)}{h} — to find the derivative of f(x)=x2f(x) = x^2. Then evaluate f(2)f'(-2).
Q10·Challenging
Use first principles to find the derivative of f(x)=3x2f(x) = 3x^2. Then find f(2)f'(2).
Q11·Challenging
Use first principles to find the derivative of f(x)=x2+5xf(x) = x^2 + 5x. Then evaluate f(0)f'(0).
Q12·Challenging
Use first principles to find the derivative of f(x)=2x23xf(x) = 2x^2 - 3x. Then evaluate f(1)f'(1).