Anti-differentiation
Recognise the indefinite integral as the reverse of differentiation; apply the standard results for , , , , and ; use the reverse chain rule.
Worked examples
Using the power rule and an initial condition
Straightforward
Problem
A function satisfies and . Find .
1
Find the general antiderivative.
Apply the power rule to each term:
2
Use the initial condition to find .
So .
3
Write the particular solution.
Answer
Integrating exponential and reciprocal functions
Moderate
Problem
Find for .
1
Integrate using the standard result .
2
Integrate .
3
Combine the results.
Answer
Reverse chain rule
Challenging
Problem
Find .
1
Spot the pattern.
Notice that is the derivative of . This is the reverse chain rule structure: where .
2
Let .
3
Substitute and integrate.
4
Back-substitute and check by differentiating.
Check: , which matches the integrand.
Answer
Practise
Q1·Straightforward
Which expression is equal to ?
Explanation
Applying with :
Q2·Straightforward
Which expression is equal to ?
Explanation
This follows directly from the fact that .
Q3·Straightforward
Which expression is equal to for ?
Explanation
This is the standard result obtained by reversing the derivative of the natural logarithm.
Q4·Straightforward
A function satisfies and . Find .
Explanation
Anti-differentiate: .
Apply the initial condition: , so .
Therefore .
Apply the initial condition: , so .
Therefore .
Q5·Straightforward
A function satisfies and . Find .
Explanation
Anti-differentiate: .
Apply the initial condition: , so .
Therefore .
Apply the initial condition: , so .
Therefore .
Q6·Moderate
Which expression is equal to ?
Explanation
Using the standard result with , :
Check by differentiating: ✓
Check by differentiating: ✓
Q7·Moderate
A function satisfies and . Find , correct to two decimal places.
Explanation
Anti-differentiate: .
Apply the condition: , so .
Therefore .
Apply the condition: , so .
Therefore .
Q8·Moderate
A function satisfies and . Find . Give your answer as a fraction.
/
Explanation
Anti-differentiate: .
Apply the condition: , so .
Therefore .
Apply the condition: , so .
Therefore .
Q9·Moderate
Which expression is equal to ?
Explanation
Since , the reverse gives:
Q10·Moderate
A function satisfies for , and . Find .
Explanation
Anti-differentiate: .
Apply the condition: , so .
Therefore .
Apply the condition: , so .
Therefore .
Q11·Challenging
Using the reverse chain rule, which expression is equal to ?
Explanation
Let , so .
Check by differentiating: ✓
Check by differentiating: ✓
Q12·Challenging
A function satisfies and . Find .
Explanation
Anti-differentiate: .
Apply the condition:
So .
Therefore .
Apply the condition:
So .
Therefore .
Q13·Challenging
A function satisfies and . Find , correct to two decimal places.
Explanation
Anti-differentiate: .
Apply the condition: , so .
Therefore .
Apply the condition: , so .
Therefore .
Open Math
Anti-differentiation
Calculus · MAV-12-05
Name:
Date:
Q1Straightforward
Which expression is equal to ?
- A.
- B.
- C.
- D.
Q2Straightforward
Which expression is equal to ?
- A.
- B.
- C.
- D.
Q3Straightforward
Which expression is equal to for ?
- A.
- B.
- C.
- D.
Q4Straightforward
A function satisfies and . Find .
Q5Straightforward
A function satisfies and . Find .
Q6Moderate
Which expression is equal to ?
- A.
- B.
- C.
- D.
Q7Moderate
A function satisfies and . Find , correct to two decimal places.
Q8Moderate
A function satisfies and . Find . Give your answer as a fraction.
Q9Moderate
Which expression is equal to ?
- A.
- B.
- C.
- D.
Q10Moderate
A function satisfies for , and . Find .
Q11Challenging
Using the reverse chain rule, which expression is equal to ?
- A.
- B.
- C.
- D.
Q12Challenging
A function satisfies and . Find .
Q13Challenging
A function satisfies and . Find , correct to two decimal places.
Worked solutions and answers at openmath.au/year-12/advanced/integral-calculus/anti-differentiation