Sine rule

Apply the sine rule asin⁡A=bsin⁡B=csin⁡C\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C} to find unknown sides and angles in non-right-angled triangles; recognise and solve the ambiguous case where two triangles are possible.

Worked examples

Finding an unknown side using the sine rule

Straightforward

Problem

In triangle ABCABC, angle A=42°A = 42°, angle B=65°B = 65°, and side a=9a = 9 cm. Find side bb.

Finding an unknown angle using the sine rule

Moderate

Problem

In triangle PQRPQR, p=7p = 7 cm, q=10q = 10 cm, and angle P=35°P = 35°. Find angle QQ (assuming it is acute).

The ambiguous case — two possible triangles

Challenging

Problem

In triangle ABCABC, a=9a = 9 cm, b=12b = 12 cm, and angle A=42°A = 42°. Show that two triangles are possible and find both possible values of angle BB.

Practise

Q1·Straightforward
In triangle ABCABC, angle A=40°A = 40°, angle B=70°B = 70°, and side a=8a = 8 cm (the side opposite angle AA). Use the sine rule to find side bb (opposite angle BB). Give your answer to 2 decimal places.
Q2·Straightforward
In triangle PQRPQR, angle P=55°P = 55°, angle Q=65°Q = 65°, and side p=12p = 12 cm (opposite angle PP). Find side qq (opposite angle QQ) using the sine rule. Give your answer to 2 decimal places.
Q3·Straightforward
In triangle ABCABC, angle A=35°A = 35°, angle C=80°C = 80°, and side a=10a = 10 cm (opposite angle AA). Find side cc (opposite angle CC). Give your answer to 2 decimal places.
Q4·Straightforward
In triangle XYZXYZ, angle X=50°X = 50°, angle Z=72°Z = 72°, and z=15z = 15 m (opposite angle ZZ). Find side xx (opposite angle XX). Give your answer to 2 decimal places.
Q5·Moderate
In triangle ABCABC, a=10a = 10 cm, b=14b = 14 cm, and angle A=32°A = 32° (opposite side aa). Assuming angle BB is acute, find angle BB to 1 decimal place.
Q6·Moderate
In triangle PQRPQR, p=8p = 8 cm, r=11r = 11 cm, and angle P=40°P = 40° (opposite side pp). Assuming angle RR is acute, find angle RR to 1 decimal place.
Q7·Moderate
In triangle ABCABC, angle A=48°A = 48°, angle B=76°B = 76°, and b=25b = 25 cm (opposite angle BB). Find side cc (opposite angle CC). Give your answer to 1 decimal place.
Q8·Moderate
Two park rangers, AA and BB, are stationed 55 km apart. They both spot a fire FF. Ranger AA measures the angle FAB=52°FAB = 52° and ranger BB measures angle FBA=71°FBA = 71°. Find the distance from ranger AA to the fire (AFAF) to 2 decimal places.
Q9·Moderate
In triangle ABCABC, angle A=65°A = 65°, angle C=42°C = 42°, and b=18b = 18 m (the side opposite angle BB). Find side aa (opposite angle AA) to 2 decimal places.
Q10·Challenging
In triangle ABCABC, a=12a = 12 cm, b=15b = 15 cm, and angle A=38°A = 38° (opposite side aa). Two triangles are possible (the ambiguous case). Find the **larger** of the two possible values of angle BB, to the nearest degree.
Q11·Challenging
A triangular block of land has vertices AA, BB and CC. Side BC=320BC = 320 m, angle ABC=68°ABC = 68°, and angle ACB=54°ACB = 54°. Find the length of side ACAC to the nearest metre.
Q12·Challenging
Points AA and BB are on opposite sides of a river. A point CC is on the same bank as AA, with AC=80AC = 80 m. From AA, the angle CAB=73°CAB = 73°; from CC, the angle ACB=52°ACB = 52°. Find the width of the river ABAB to the nearest metre.